![]() Check out the answer and explanation below.Ģ72 grams / (44.01 g/mol) * (6.02*10^23 molecules/mol) * (2 O atoms/molecule) = 7.441*10^24 oxygen atoms You have to add another conversion factor in here at the end. How many grams are in 1.12*10^22 molecules of SF6?įor grams to particles, the process is very similar except now instead of multiplying by the molar mass, we are dividing and instead of multiplying by Avogadro's number, we are multiplying! We are going to look at a similar problem to the one above except this one is a bit trickier!Įxample 1: How many atoms of oxygen are in 272 grams of carbon dioxide?Īnswer: In this problem you are asked for a final answer of atoms of oxygen but you are dealing with a compound. How many grams are in 2.2*10^24 atoms of gold?Ģ. ![]() ![]() If doing the problem in separate steps helps, then do it! You do not have to do it all in one!ġ. This may seem confusing but all you are doing is combining a particle to moles conversion and a moles to gram conversion. Since we are converting with grams, we need the molar mass first which is 1 Fe and 3 Cl = 162.20 g/mol, once you have that then you can start your conversion. If you criss cross the charges, you end up with FeCl3. Iron's roman numeral tells you it has a +3 charge and chloride is always -1. You have to divide and then multiply again but first you must figure out the formula for the compound. figs.).Įxample 2: How many grams are in 3.116 *10^22 formula units of Iron (III) chloride? so we are only limited by the number we start with, in this case, 4.29 (3 sig. In terms of significant figures, we assume conversion factors such as molar mass have an infinite number of sig. Then when you multiply by the molar mass, the mole unit is present on both the top and the bottom so it cancels out leaving you with just grams. When you divide by 6.02*10^23 atoms/mol, atoms is present on both top and bottom, so it cancels out. You are converting from atoms to grams, so you must divide by 6.02*10^23 atoms/mol and then MULTIPLY by the molar mass of copper which is found on the periodic table. Example 1: How many grams are in 4.29 *10^24 atoms of copper?
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